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8a^2-26a+21=0
a = 8; b = -26; c = +21;
Δ = b2-4ac
Δ = -262-4·8·21
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2}{2*8}=\frac{24}{16} =1+1/2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2}{2*8}=\frac{28}{16} =1+3/4 $
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